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Using van der Waals equation determine the pressure exerted by 3.00 mol of Ar gas with a volume of 50.0 L at 25.0 °C.
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Answers ( )
Answer:
1.47 atm
Explanation:
From the question.
Applying
PV = nRT…………….. Equation 1
Where P = pressure, V = volume, T = temperature, n = number of moles, R = Molar gas constant
Makr P the subject of the equation
P = nRT/V……………. Euqation 2
Given: V = 50.0 L, n = 3.00 mol, T = 25°C = (273+25) = 298K,
Constant: R = 0.082 atm.L.K⁻¹mol⁻¹
Substitute these values into equation 2
P = (3×298×0.082)/(50)
P = 73.308/50
P = 1.46616
P ≈ 1.47 atm