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Using the ideal gas law, what will be the volume occupied by 1.46 moles of helium at 0.982 atmospheres and 13.0°C? (R = 0.0821 L’atm/m
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Answers ( )
Answer:
34.91 L
Explanation:
Ideal gas law -> PV=nRT
convert C to K -> 13+273 = 286
plug numbers in
(.982)V=(1.46)(.0821)(286)
V = 34.91 L