Using a conventional two-slit apparatus with light of wavelength 605 nm, 34 bright fringes per centimeter are observed on a screen 3.1 m awa

Question

Using a conventional two-slit apparatus with light of wavelength 605 nm, 34 bright fringes per centimeter are observed on a screen 3.1 m away. What is the slit separation

in progress 0
Thành Đạt 6 months 2021-08-10T05:30:09+00:00 1 Answers 7 views 0

Answers ( )

    0
    2021-08-10T05:31:24+00:00

    Answer:

    d = 6.38 x 10⁻³ m = 6.38 mm

    Explanation:

    Since, the no. of bright fringes is 34 in a centimeter, therefore, the fringe spacing must be equal to:

    Fringe Spacing = Δx = 1 cm/34

    Δx = 0.0294 cm = 2.94 x 10⁻⁴ m

    But, the formula for fringe spacing in a double slit experiment is:

    Δx = λL/d

    where,

    λ = wavelength of light = 605 nm = 6.05 x 10⁻⁷ m

    L = Distance between screen and slits = 3.1 m

    d = slit separation = ?

    Therefore,

    2.94 x 10⁻⁴ m = (6.05 x 10⁻⁷ m)(3.1 m)/d

    d = (18.755 x 10⁻⁷ m²)/(2.94 x 10⁻⁴ m)

    d = 6.38 x 10⁻³ m = 6.38 mm

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )