Use the discriminant to determine the number of real solutions to the quadratic equation. 6a2−11a+9=0 What is the number of real

Question

Use the discriminant to determine the number of real solutions to the quadratic equation.
6a2−11a+9=0
What is the number of real solutions?
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Farah 3 years 2021-08-24T04:21:43+00:00 1 Answers 34 views 0

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  1. ngockhue
    0
    2021-08-24T04:23:04+00:00
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    Answer:

    0

    Step-by-step explanation:

    Use discramnt formula

    b {}^{2} - 4ac

    Where 6 is a, 11 is b and 9 is c

    11 {}^{2} - 4(6)(9)

    121 - 216 = - 95

    Since the discramnt is negative, there are no real solutions and it will only produce imaginary solutions

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )