Use technology or a z-score table to answer the question. The number of baby carrots in a bag is normally distributed with a mea

Question

Use technology or a z-score table to answer the question.

The number of baby carrots in a bag is normally distributed with a mean of 94 carrots and a standard deviation of 8.2 carrots.

Approximately what percent of the bags of baby carrots have between 90 and 100 carrots?

23.3%

31.2%

45.5%

76.73%

in progress 0
Đan Thu 4 years 2021-08-22T22:20:38+00:00 1 Answers 9 views 0

Answers ( )

  1. hongcuc2
    0
    2021-08-22T22:22:32+00:00
    Reply

    Answer:

    46% is the percent of the bags of baby carrots that have between 90 and 100 carrots

    Step-by-step explanation:

    The baby carrot is normally distributed.  

    z = (x – µ)/σ

    x is equal to number of baby carrots  

    µ = mean

    σ = standard deviation

    Substituting the given values, we get –

    90 ≤ x ≤ 100

    z = (90 – 94)/8.2 = – 0.49

     For z value of -0.49, the probability is 0.31

    For x = 100

    z = (100 – 94)/8.2 = 0.73

    For z value of 0.73, the probability is 0.77

    P(90 ≤ x ≤ 100) = 0.77 – 0.31 = 0.46

    The percent of the bags of baby carrots having carrots between 90 and 100 carrots is  0.46 × 100 = 46%

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )