*Urgent* A balloon has a volume of 31.8 L at a temperature of 46 degrees C. What is the new temperature of the balloon in degree

Question

*Urgent*
A balloon has a volume of 31.8 L at a temperature of 46 degrees C. What is the new temperature
of the balloon in degrees C if the volume is changed to 49.2 liters?
Round answers to 0.1 decimals

in progress 0
Maris 3 years 2021-09-05T00:27:33+00:00 1 Answers 4 views 0

Answers ( )

  1. Tryphena
    0
    2021-09-05T00:29:12+00:00
    Reply

    Answer:

    The new volume will be  

    0.7 L

    Explanation:

    This is an illustration of Charles’ law, some of the time called the temperature-volume law. It expresses that the volume of a gas is straightforwardly corresponding to the Kelvin temperature, while pressing factor and sum are held steady.  The condition is  V  1  T  1  =  V  2  T  2  , where  V  is volume and  T  is temperature in Kelvins.  Known  V  1  =  0.5 L  T  1  =  20  ∘  C  +  273.15  =  293 K  T  2  =  150  ∘  C  +  273.15  =  423 K  Obscure  V  2  Arrangement  Revise the condition to confine  V  2  . Substitute the known qualities into the condition and address.  V  2  =  V  1  T  2  T  1  V  2  =  (  0.5  L  ×  423  K  )  293  K  =  0.7 L  adjusted to one huge figure

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )