Uranium was used to generate electricity in a nuclear reactor of a nuclear power station. The nuclear reactor was 29% efficient and the powe

Question

Uranium was used to generate electricity in a nuclear reactor of a nuclear power station. The nuclear reactor was 29% efficient and the power output was 800MW. The fuel used in this plant contained 4% of pure uranium. The plant operated 365 days per year. The average price of the fuel during the first 20 years of operation of the plant was US$12/lb, but in last 20 years of operation, the price spiked to US$65/lb. Calculate the cost of fuel for the lifetime of the plant, 40

in progress 0
Edana Edana 5 months 2021-08-29T01:04:23+00:00 1 Answers 3 views 0

Answers ( )

  1. danthu
    0
    2021-08-29T01:05:55+00:00
    Reply

    Answer:

    C_{lifetime} = 2,618,017,174\,USD

    Explanation:

    The energy contained per second in the fuel is:

    \dot E_{fuel} = \frac{800\times 10^{6}\,W}{0.29}

    \dot E_{fuel} = 2.758\times 10^{9}\,W

    It is know that fission of a gram of uranium liberates 5.8\times 10^{8}\,J. Mass flow rate is computed herein:

    \dot m_{U}= \frac{2.758\times 10^{9}\,W}{5.8\times 10^{8}\,\frac{J}{g}}

    \dot m_{U} = 4.755\,\frac{g}{s}

    The needed quantity of fuel per second is:

    \dot m_{fuel} = \frac{4.755\,\frac{g}{s} }{0.04}

    \dot m_{fuel} = 118.875\,\frac{g}{s}

    The annual fuel consumption is now obtained:

    \Delta m_{fuel,year} = (0.119\,\frac{kg}{s})\cdot (\frac{3600\,s}{1\,h} )\cdot (\frac{24\,h}{1\,day} )\cdot(\frac{365\,days}{1\,year} )

    \Delta m_{fuel,year} = 3,752,784\,\frac{kg}{year}

    The cost of fuel for the lifetime of the plant is:

    C_{lifetime} = (3,752,784\,\frac{kg}{year} )\cdot (\frac{0.453\,lb}{1\,kg} )\cdot [(20\,years)\cdot(\frac{12\,USD}{1\,lb} )+(20\,years)\cdot (\frac{65\,USD}{1\,lb} )

    C_{lifetime} = 2,618,017,174\,USD

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )