Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and the axis of th

Question

Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and the axis of the second is rotated θ = 65° from the vertical.

Required:
a. What is the intensity of the light after it passes through the first polarizer in W/m2?
b. What is the intensity of the light after it passes through the second polarizer in W/m2?

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Kim Chi 5 months 2021-08-15T01:00:21+00:00 1 Answers 12 views 0

Answers ( )

    0
    2021-08-15T01:01:51+00:00

    Answer:

    Intensity of the light (first polarizer) (I₁) = 425 W/m²

    Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

    Explanation:

    Given:

    Unpolarized light of intensity (I₀) = 950 W/m²

    θ = 65°

    Find:

    a. Intensity of the light (first polarizer)

    b. Intensity of the light (second polarizer)

    Computation:

    a. Intensity of the light (first polarizer)

    Intensity of the light (first polarizer) (I₁) = I₀ / 2

    Intensity of the light (first polarizer) (I₁) = 950 / 2

    Intensity of the light (first polarizer) (I₁) = 425 W/m²

    b. Intensity of the light (second polarizer)

    Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

    Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

    Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )