Una sirena que emite un sonido de f=100Hz se mueve alejandose de un observador en reposo y dirigiendose hacia un acantilado con velocidad co

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Una sirena que emite un sonido de f=100Hz se mueve alejandose de un observador en reposo y dirigiendose hacia un acantilado con velocidad constante de v1=20 m/s.

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Kim Chi 3 years 2021-08-19T11:34:14+00:00 1 Answers 3 views 0

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  1. Cherry
    0
    2021-08-19T11:35:16+00:00
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    Given that,

    Frequency = 100 Hz

    Velocity = 20 m/s

    Suppose, Determinar la diferencia de  frecuencia entre la onda que recibe el observador directamente de la sirena y la onda que le llega reflejada  en el acantilado.

    We need to calculate the frequency heard by the observer directly from source

    Using formula of frequency

    f_{1}=f\times(\dfrac{v}{v-v_{s}})

    Where, v = speed of sound

    v_{s} = speed of source

    f = frequency of source

    Put the value into the formula

    f_{1}=100\times\dfrac{340}{340-20}

    f_{1}=106.25\ Hz

    We need to calculate the frequency heard by the observer coming after reflection from cliff

    Using formula of frequency

    f_{2}=f\times(\dfrac{v}{v+v_{s}})

    Put the value into the formula

    f_{2}=100\times\dfrac{340}{340+20}

    f_{2}=94.4\ Hz

    We need to calculate the difference of  frequency

    Using formula for difference of  frequency

    \Delta f=f_{1}-f_{2}

    Put the value into the formula

    \Delta f=106.25-94.4

    \Delta f=11.85\ Hz

    Hence, The difference of frequency is 11.85 Hz.

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