Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the other pulls in

Question

Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate’s coefficient of kinetic friction on the floor

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Ngọc Hoa 1 week 2021-07-22T01:10:34+00:00 1 Answers 0 views 0

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    2021-07-22T01:12:33+00:00

    Answer:

    The crate’s coefficient of kinetic friction on the floor is 0.23.

    Explanation:

    Given that,

    Mass of the crate, m = 300 kg

    One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate.

    The crate slides with a constant speed. It means that the net force acting on it is 0. Net force acting on it is given by :

    F_1+F_2=\mu N\\\\\mu=\dfrac{F_1+F_2}{mg}\\\\\mu=\dfrac{390+320}{300\times 10}\\\\\mu=0.23

    So, the crate’s coefficient of kinetic friction on the floor is 0.23.

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