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## Two wires carry current I1 = 47 A and I2 = 29 A in the opposite directions parallel to the x-axis at y1 = 9 cm and y2 = 15 cm. Where on the

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## Answers ( )

Answer:Approximately , assuming that the permeability between the two wires is constant, and that the two wires are of infinite lengths.

Explanation:Note that , which means that the first wire (with current ) is underneath the second wire (with current .) Let denote the -coordinate (in ) of a point of interest. The two wires partition this region into three parts:

Apply the right-hand rule to find the direction of the magnetic field in each of the three regions. Assume that points to the left while points to the right. Let and denote the magnetic field due to and , respectively.

The (net) magnetic field on this plane would be zero only in regions where and points in opposite directions. That rules out the region between the two wires.

At a distance of away from a wire with current and infinite length, the formula for the magnitude of the magnetic field due to that wire is:

,

where is the permeability of the space between the wire and the point of interest (should be constant.) The exact value of does not affect the answer to this question, as long as it is constant throughout this region.

Note that the value of in this formula is supposed to be positive. Let and denote the distance between the point of interest and the two wires, respectively.

Make sure that given the corresponding range of , these distances are all positive.

For the net magnetic field to be zero at a certain -value, the strength of the two magnetic fields at that point should match. That is:

.

.

Simplify this equation:

.

These two equations give the same result: . However, based on the respective assumptions on the value of , this value corresponds to the region above the second wire.