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Two weights are connected by a very light cord that passes over an 80.0 N frictionless pulley of radius 0.300 m. The pulley is a solid unifo
Question
Two weights are connected by a very light cord that passes over an 80.0 N frictionless pulley of radius 0.300 m. The pulley is a solid uniform disk and is supported by a hook connected to the ceiling. What force does the ceiling exert on the hook
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Physics
6 months
2021-07-21T02:06:50+00:00
2021-07-21T02:06:50+00:00 1 Answers
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Answers ( )
Answer:
The force the ceiling exert on the hook is 321.67 N
Explanation:
Here we have the weights being 75 N and 125 N
The weight of the pulley = 80 N
Total weight hung from the ceiling = 75 + 125 + 80 = 280 N
Therefore since the forces acting on the ceiling tends to act downwards as they are the forces due to weights, we have
The force on the
T₁ – 125 = m₂a =
m₂ = 125/9.8 = 12.76 kg
Similarly T₂ – 75 = m₁a, m₁ = 7.65 kg
acceleration is given by
Therefore
T₁ – 125 = m₂a = 12.76 × 2.042 = 26.04 N and
T₁ = 125 + 26.04 = 151.04 N
Similarly T₂ – 75 = m₁a = 7.65 × 2.042 = 15.63 N
T₂ = 15.63 + 75 = 90.63 N
Force on hook = Force exerted by ceiling on hook = T₁ + T₂ + Weight of pulley = 151.04 + 90.63 + 80 = 321.67 N