Two small silver spheres, each of mass m=6.2 g, are separated by distance d=1.2 m. As a result of transfer of some fraction of electrons fro

Question

Two small silver spheres, each of mass m=6.2 g, are separated by distance d=1.2 m. As a result of transfer of some fraction of electrons from one sphere to the other, there is an attractive force F=900 KN between the spheres. Calculate the fraction of electrons transferred from one of the spheres: __________

To evaluate the total number of electrons in a silver sphere, you will need to invoke Avogadro’s number, the molar mass of silver equal to 107.87 g/mol and the fact that silver has 47 electrons per atom.

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Jezebel 1 day 2021-07-22T09:35:11+00:00 1 Answers 0 views 0

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    2021-07-22T09:37:06+00:00

    Answer:

    4.60 × 10⁻⁸

    Explanation:

    From the given information;

    Assuming that q charges are transferred, then:

    F = \dfrac{kq^2}{d^2}

    where;

    k = 9 ×10⁹

    900000 = \dfrac{9*10^9 \times q^2}{1.2^2}

    q = \sqrt{\dfrac{900000\times 1.2^2 }{9*10^9}}

    q = 0.012 C

    No of the electrons transferred is:

    = \dfrac{0.012}{1.6\times 10^{-19}} C

    = 7.5 \times 10^{16} \ C

    Initial number of electrons =  N × 47 × no  of moles

    here;

    \text{ no of moles }= \dfrac{6.2}{107.87}

    no of moles = 0.0575 mol

    Initial number of electrons =  6.023\times 10^{23} \times 47 \times 0.0575 mol

    = 1.63 × 10²⁴

    The fraction of electrons transferred  =\dfrac{7.5\times 10^{16} }{1.6 3\times 10^{24}}

    = 4.60 × 10⁻⁸

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