Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them has magnitude

Question

Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them has magnitude 0.200 N . Part A What is the charge on each sphere if the two charges are equal

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Ben Gia 4 years 2021-08-18T21:59:05+00:00 1 Answers 42 views 0

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  1. Calantha
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    2021-08-18T22:00:49+00:00
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    Answer:

    q = 7.542 x 10⁻⁷ C = 754.2 nC

    Explanation:

    The Coulomb’s Law gives the magnitude of the force of attraction or repulsion between two charges:

    F = kq₁q₂/r²

    where,

    F = Force of attraction or repulsion = 0.2 N

    k = Coulomb’s Constant = 9 x 10⁹ N m²/C²

    r = distance between charges = 16 cm = 0.16 m

    q₁ = magnitude of 1st charge

    q₂ = magnitude of 2nd charge

    Since, both charges are said to be equal here.

    q₁ = q₂ = q

    Therefore,

    0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²

    (0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²

    q = √(5.88 x 10⁻¹³ C²)

    q = 7.542 x 10⁻⁷ C = 754.2 nC

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