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Two slits in an opaque barrier each have a width of 0.020 mm and are separated by 0.050 mm. When coherent monochromatic light passes through
Question
Two slits in an opaque barrier each have a width of 0.020 mm and are separated by 0.050 mm. When coherent monochromatic light passes through the slits the number of interference maxima within the central diffraction maximum: Group of answer choices is 1 is 4 is 2 is 5 cannot be determined unless the wavelength is given
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3 years
2021-08-05T19:40:53+00:00
2021-08-05T19:40:53+00:00 1 Answers
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Answers ( )
Answer:
The answer is 5
Explanation:
The maximum interference is:
m * λ = d * sinθi
Where m = 0,1,2,3,…
The first minimum diffraction is:
λ = a * sinθd
|sinθi| < sinθd
Where
(|m| * λ)/d < λ/a
|m| < d/a = 2.5
|m|max = 2
It can be concluded that coherent monochromatic light passes through the slits, therefore the maximum number of interference is 5.