Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?

Question

Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?

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Kim Chi 3 weeks 2021-08-22T18:58:02+00:00 1 Answers 0 views 0

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    2021-08-22T18:59:07+00:00

    Answer:

    7.45 Ω

    Explanation:

    From the question given above, the following data were obtained:

    Resistor 1 (R₁) = 2.50 Ω

    Resistor 2 (R₂) = 4.95 Ω

    Voltage (V) = 12 V

    Equivalent Resistance (Rₑq) =?

    Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:

    Rₑq = R₁ + R₂

    Rₑq = 2.5 + 4.95

    Rₑq = 7.45 Ω

    Therefore, the equivalent resistance is 7.45 Ω

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