Two positive numbers have a difference of 21. The larger number is five more than twice the smaller. Find the two numbers.

Question

Two positive numbers have a difference of 21. The larger number is five more than twice the smaller. Find the two numbers.

in progress 0
Delwyn 3 months 2021-08-21T22:52:51+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-21T22:54:05+00:00

    Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then …

    Let 2n + 5 = the second and larger number.

    Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
    n + (2n + 5) = 26

    n + 2n + 5 = 26

    Collecting like-terms on the left, we get:
    3n + 5 = 26

    3n + 5 – 5 = 26 – 5

    3n + 0 = 21

    3n = 21

    (3n)/3 = 21/3

    (3/3)n = 21/3

    (1)n = 7

    n = 7

    Therefore, …
    2n + 5 = 2(7) + 5
    = 14 + 5
    = 19

    CHECK:
    n + (2n + 5) = 26
    7 + (19) = 26
    7 + 19 = 26
    26 = 26

    Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.

    Hope this helps 🙂

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )