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Two positive charges, 91 = 5 x 10-‘[C] and q2 =1 x 10-9 [C], are separated by a distance of d=0.05 m. At location ‘P’ between the
Question
Two positive charges, 91 = 5 x 10-‘[C] and q2 =1 x 10-9 [C], are
separated by a distance of d=0.05 m. At location ‘P’ between the
two charges, the net electric field is found to be zero.
b. [10 points] The distance between charge qı and location ‘P’ is
considered to be ‘x’. Find the value of ‘x’ in [cm]
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Physics
3 years
2021-07-14T02:49:10+00:00
2021-07-14T02:49:10+00:00 1 Answers
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Answer:
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