Two positive charges, 91 = 5 x 10-‘[C] and q2 =1 x 10-9 [C], are separated by a distance of d=0.05 m. At location ‘P’ between the

Question

Two positive charges, 91 = 5 x 10-‘[C] and q2 =1 x 10-9 [C], are
separated by a distance of d=0.05 m. At location ‘P’ between the
two charges, the net electric field is found to be zero.

b. [10 points] The distance between charge qı and location ‘P’ is
considered to be ‘x’. Find the value of ‘x’ in [cm]

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Doris 4 months 2021-07-14T02:49:10+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-14T02:50:32+00:00

    Answer:

    wareffctgggyyggghhhh

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