Two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N . If a charge of -5 micro coulomb is added to e

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Two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N . If a charge of -5 micro coulomb is added to each of them, then the force between them will become?

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Bình An 2 days 2021-07-22T19:22:29+00:00 1 Answers 2 views 0

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    2021-07-22T19:24:27+00:00

    Answer:

    1 N

    Explanation:

    Given that two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N.

    Let us first calculate the distance between the two point charges

    F = (KQq)/r^2

    Where K = 9.0 × 10^9Nm^2C^-2

    40 = (9×10^9 × 3×10^-6 × 8×10^-6)/r^2

    Make r^2 the subject of formula

    r^2 = 0.216/40

    r = sqrt (5.4^-3)

    r = 0.0735 metres

    If a charge of -5 micro coulomb is added to each of them, then the force between them will become?

    Using the same formula again

    F = ( KQq)/r^2

    Where Q = 8 – 5 = +3 × 10^-6 C

    q = 3 – 5 = – 2 × 10^-6 C

    F = ( 9×10^9 × 3×10^-6 × 2×10^-6 )/5.4×10^-2

    F = 0.054/0.054

    F = 1 N

    The force of attraction between the two point charges will be 1 N

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )