Two people are sitting on playground swings. One is pulled back 4 degrees from the vertical and the other is pulled back 8 degrees. They are

Two people are sitting on playground swings. One is pulled back 4 degrees from the vertical and the other is pulled back 8 degrees. They are both released at the same instant. Will they both come back to their starting points at the same time

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  1. Answer:

    They will come back at the same time.

    Explanation:

    The angular velocity equation of ω[tex]= \frac{V}{r}[/tex] where ω is the frequency of the movement, dependent on the angle. But since swings are simple pendulums and their angles of 8 and 4 degrees are small, they will come back to their starting points at the same time.

    I hope this answer helps.

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  2. Answer:

    The bodies will not come back to their starting point at he same time.

    Explanation:

    Since they are both pulled back at an angle to the vertical, there is a tangential component of acceleration a = gsinθ

    When θ = 4 , a = 9.8sin4 = 0.684 m/s²

    When θ = 8 , a = 9.8sin8 = 1.364 m/s²

    Using s = ut + 1/2at². Where s is the distance covered and t = time taken, u = initial speed = 0 (assumed since they are both released at the same time)

    So s = 0 × t + 1/2at² = 1/2at²

    s = 1/2at²

    t = √2s/a. Now, since s is the same for both swings, it follows that

    t ∝ 1/a. Since their accelerations are different, the bodies will not come back to their starting point at he same time.

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