Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, parti

Question

Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg

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Cherry 2 months 2021-07-22T14:15:42+00:00 1 Answers 2 views 0

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    2021-07-22T14:17:11+00:00

    Answer:

    a)  q=4.92*10^{-8} C

    b)  m=4.026*10^{-6} kg

    Explanation:

    From the question we are told that:

    Separation distance d=2.65*10^{-2} m

    Acceleration 1 a_1=5.00*10^3 m/s^2,

    Acceleration 2 a_2=7.70*10^3 m/s^2,

    Mass 1 m_1=6.20*10^{-6}

    Generally the equation for Force is mathematically given by

     F=ma

    For Particle 1

     F=6.2*10^{-6} *5*10^3

     F=0.031 N

    Also

     F=\frac{kq_1*q2}{r^2}

    Where

     q_1=q_2

    Therefore

     0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}

     q=4.92*10^{-8} C

    b)

    Generally the equation for Force is mathematically given by

     F=ma

     0.031=7.7*10^3

     m=4.026*10^{-6} kg

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