Two particles, one with charge − 7.97 μC and one with charge 3.55 μC, are 6.59 cm apart. What is the magnitude of the force that one particl

Two particles, one with charge − 7.97 μC and one with charge 3.55 μC, are 6.59 cm apart. What is the magnitude of the force that one particle exerts on the other?

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  1. Answer:

    58.6 N

    Explanation:

    We are given that

    [tex]q_1=-7.97\mu C=-7.97\times 10^{-6} C[/tex]

    [tex]q_2=3.55\mu C=3.55\times 10^{-6} C[/tex]

    Using [tex]1\mu C=10^{-6} C[/tex]

    [tex]r=6.59 cm=6.59\times 10^{-2} m[/tex]

    [tex]1 cm=10^{-2} m[/tex]

    The magnitude of force that one particle exerts on the other

    [tex]F=\frac{kq_1q_2}{r^2}[/tex]

    Where [tex]k=9\times 10^9[/tex]

    Substitute the values

    [tex]F=\frac{9\times 10^9\times 7.97\times 10^{-6}\times 3.55\times 10^{-6}}{(6.59\times 10^{-2})^2}[/tex]

    F=58.6 N

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