Two particles experience an attractive electric force of 5 N. If one of the charges triples and the distance between them doubles, wha

Question

Two particles experience an attractive electric force of 5 N. If one of the charges triples and
the distance between them doubles, what is the new electric force?

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Thành Công 4 years 2021-07-30T14:30:40+00:00 1 Answers 47 views 0

Answers ( )

  1. phucdien
    0
    2021-07-30T14:31:46+00:00
    Reply

    3.75 N

    Explanation:

    F = k(q)(q)/r^2 = 5 N

    F’ = k(q)(3q)/(2r)^2

    = k×3(q)(q)/4r^2

    = (3/4)[k(q)(q)/r^2]

    = (3/4)F

    = (3/4)(5 N)

    = 3.75 N

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