Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field streng

Question

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate

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Hồng Cúc 4 years 2021-07-20T09:42:08+00:00 1 Answers 256 views 0

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  1. Delwyn
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    2021-07-20T09:43:39+00:00
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    Complete Question

    Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate(and 2.00 cm from the other) is 450 V?

    Answer:

    V'=562.5v

    Explanation:

    From the question we are told that:

    Separation distance d=10cm

    Voltage at 8cm V_8=450v

    Generally the equation for Voltage is mathematically given by

    |V|=|E.d|

    Where

    E=electric field

    Therefore

    At d=0.8

     (450-0)V=E*(0.08m)

     E=\frac{450}{0.08}

     E=5625v/m

    Therefore

     At d=10

     V'=Ed

     V'=5625*0.1m

     V'=562.5v

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