Two of the types of infrared light, IR-B and IR-A, are both components of sunlight. Their wavelengths range from 1400 to 3000 nm for IR-B an

Question

Two of the types of infrared light, IR-B and IR-A, are both components of sunlight. Their wavelengths range from 1400 to 3000 nm for IR-B and from 700 to 1400 nm for IR-A. Compare the energy of microwaves, IR-B, and IR-A. Rank from greatest to least energy per photon. To rank items as equivalent, overlap them.

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Hải Đăng 4 years 2021-09-05T01:04:50+00:00 1 Answers 83 views 0

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  1. Orla
    0
    2021-09-05T01:06:47+00:00
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    Answer:

    The IR-A is the greatest energy per photon compare to that of IR-B.

    Explanation:

    Given that,

    Wavelength of (IR-B)= 1400 nm

    Wavelength of (IR-A)= 700 nm

    We need to calculate the energy for IR-B

    Using formula of energy

    E=\dfrac{hc}{\lambda}

    Put the value into the formula

    E=\dfrac{6.62\times10^{-34}\times3\times10^{8}}{1400\times10^{-9}}

    E=1.418\times10^{-19}\ J

    The energy for IR-B is 1.418\times10^{-19}\ J

    We need to calculate the energy for IR-A

    Using formula of energy

    E=\dfrac{hc}{\lambda}

    Put the value into the formula

    E=\dfrac{6.62\times10^{-34}\times3\times10^{8}}{700\times10^{-9}}

    E=2.83\times10^{-19}\ J

    The energy for IR-B is 2.83\times10^{-19}\ J

    Hence, The IR-A is the greatest energy per photon compare to that of IR-B.

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