Two negative charges that are both – 3.8 C push each other apart with a force of 19.0 N. How far apart are the two charges?

Question

Two negative charges that are both – 3.8 C push each other apart with a force of 19.0 N. How far apart are the two charges?

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Thanh Thu 3 years 2021-07-26T10:02:13+00:00 1 Answers 17 views 0

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  1. Thunguyet
    0
    2021-07-26T10:03:45+00:00
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    Answer:

    The separation distance between the two charges must be 82704.2925 m

    Explanation:

    Given:

    Two negative charges that are both q = -3.8 C

    Force of 19 N

    Question: How far apart are the two charges, s = ?

    First, you need to get the electrostatic force of this two negative charges:

    F=\frac{kq}{s^{2} } \\s=\sqrt{\frac{kq}{F} }

    Here

    k = electric constant of the medium = 9×10⁹N m²/C²

    Substituting values:

    s=\sqrt{\frac{9x10^{9}*(-3.8)^{2} }{19} } =82704.2925m

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