Two narrow parallel slits (separated by the distance d = 0.9 mm) are illuminated by monochromatic light with lambda = 550 nm. The two slits

Question

Two narrow parallel slits (separated by the distance d = 0.9 mm) are illuminated by monochromatic light with lambda = 550 nm. The two slits create a diffraction pattern of bright and dark spots. Find the smallest angle theta1 (in degrees) at which the rays from the two slits create a bright spot.

in progress 0
Thu Hương 6 months 2021-07-21T01:59:27+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-21T02:01:13+00:00

    Answer:

       The smallest angle is    \theta = 0.00061^o

    Explanation:

    From the question we are told that

      The distance of separation is  d = 0.9 mm

       The wavelength is \lambda = 550nm

    General the location of the interference fringes is mathematically represented by

             dsin \theta = m \lambda

    m is the order of the fringe

    Now the smallest angle at which both ray create a bright spot would be when

    m= 1

        dsin \theta =  \lambda

       sin \theta =\frac{\lambda}{d}

           \theta  = sin ^{-1} (\frac{\lambda}{d} )

    Substituting values

         \theta = sin ^{-1}(\frac{550*10^{-9}}{0.9*10^{-3}} )

           = sin^{-1}(0.0006111)

       \theta = 0.00061^o

           

           

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )