Two monatomic ideal gases are in thermal equilibrium with each other. Gas A is composed of molecules with mass m while gas B is composed of

Question

Two monatomic ideal gases are in thermal equilibrium with each other. Gas A is composed of molecules with mass m while gas B is composed of molecules with mass 4m. The ratio of the average molecular kinetic energy KA / KB is

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RobertKer 4 years 2021-08-07T19:04:16+00:00 1 Answers 192 views 0

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    2021-08-07T19:06:15+00:00

    Answer: \frac{K_{A}}{K_{B}} = 1

    Explanation: Average molecular kinetic energy for monatomic idela gases is given by:

    E=\frac{3}{2}RT

    where

    R is gas constant of ideal gas

    T is temperature

    Which means kinetic energy depnends only on temperature.

    Since gas A and gas B are at the same temperature, kinetic energy will be the same. Therefore:

    \frac{K_{A}}{K_{B}} = 1

    Ratio of this average molecular kinetic energy is 1.

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