## Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wall. The speak

Question

Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4450 Hz. What is the phase difference ∆Φ between the two waves (generated by each speaker) when they reach the listener? The speed of the sound in air is 343 m/s. Answer in units of rad.

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6 months 2021-07-20T12:14:11+00:00 1 Answers 11 views 0

The phase difference is

Explanation:

From the question we are told that

The distance between the  loudspeakers is

The distance of the listener from the wall

The frequency of the  loudspeakers is

The velocity of sound is

The path difference of the sound wave that is getting to the listener is mathematically represented as

Substituting values

The phase difference is mathematically represented as

=

Where is the wavelength which is mathematically represented as

substituting value

Substituting value into the  equation for phase difference

=