Two long, parallel wires are separated by a distance of 3.80 cm . The force per unit length that each wire exerts on the other is 4.90×10−5

Question

Two long, parallel wires are separated by a distance of 3.80 cm . The force per unit length that each wire exerts on the other is 4.90×10−5 N/m , and the wires repel each other. The current in one wire is 0.540 A .(a) What is the current in the second wire? (b) Are the two currents in the same direction or in opposite directions?

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Thành Đạt 2 months 2021-07-29T05:19:30+00:00 1 Answers 5 views 0

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    2021-07-29T05:20:36+00:00

    Answer:

    (a). I’ = 17.24 A

    (b).The current in second wire is in opposite direction compare to first wire.

    Explanation:

    Given data

    r = 0.038 m

    \frac{F}{L} = 4.9 × 10^{-5} \frac{N}{m}

    I = 0.54 A

    (a). The current in the second wire is calculated as

    I'=\frac{F}{L} \frac{2 \pi r}{\mu I}

    Put all the values in above formula we get

    I' = \frac{ (2) (3.14) (0.038)}{4 \pi (0.54)} 490

    I’ = 17.24 A

    (b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.

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