Two inductors are placed in a circuit in series with each other. Inductor 1 has an inductance of 3.5e-3 H and inductor 2 has an inductance o

Question

Two inductors are placed in a circuit in series with each other. Inductor 1 has an inductance of 3.5e-3 H and inductor 2 has an inductance of 1.38e-4 H. Anytime current is running through the inductors, what is the ratio of energy stored in inductor 1 compared to inductor 2? U1 is the energy in inductor 1 and U2 is the energy in inductor 2.

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Jezebel 3 months 2021-08-02T14:52:06+00:00 1 Answers 4 views 0

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    2021-08-02T14:54:04+00:00

    Answer:

    Ratio of energy stored in the inductor will be 2.536

    Explanation:

    We have given two inductance L_1=3.5\times 10^{-3}H

    L_2=1.38\times 10^{-4}H

    As inductors  are connected in series so current will be same in both inductor

    Energy stored in inductor is equal to \frac{1}{2}Li^2

    U_1=\frac{1}{2}\times 3.5\times 10^{-3}\times i^2......EQN 1

    Energy stored in second inductor

    U_2=\frac{1}{2}\times 1.38\times 10^{-4}\times i^2......EQN 2

    Dividing equation 1 by equation 2

    \frac{U_1}{U_2}=\frac{\frac{1}{2}\times 3.5\times 10^{-3}i^2}{\frac{1}{2}\times 1.38\times 10^{-4}i^2}=2.536

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