Share

## . Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. The first veh

Question

. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. The first vehicle collides with a concrete barrier, and stops in a time of approximately 0.1 s. The second vehicle collides with a collapsible barrier, and comes to rest in about 1 second. Which object is subject to a larger force

in progress
0

Physics
1 month
2021-08-16T02:56:57+00:00
2021-08-16T02:56:57+00:00 1 Answers
0 views
0
## Answers ( )

Answer:F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:For this exercise let’s use the relationship between momentum and momentum.

I = F t = Δp

in this case the final velocity is zero

F t = 0 -m v₀

F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

F₁ = -p₀ / 0.1

F₁ = – 10 p₀

barrier collapses

F₂ = -p₀ / 1

let’s look for the relationship of the forces

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier