Two identical charges , 2.0m apart , exert forces of magnitude 4.0N on each other . The value of either charge is : ( ke= 9*10^9 N.M^2 .C^-2

Question

Two identical charges , 2.0m apart , exert forces of magnitude 4.0N on each other . The value of either charge is : ( ke= 9*10^9 N.M^2 .C^-2)

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Thu Nguyệt 6 months 2021-07-26T22:05:31+00:00 1 Answers 26 views 0

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    2021-07-26T22:06:49+00:00

    Answer:

    4.216 * 10^(-5) C

    Explanation:

    Parameters given:

    Electrostatic force between charges, F = 4N

    Distance between the charges, r = 2 m

    The electrostatic force acting between two charged particles, q1 and q2, separated by a distance, r, is given as:

    F = (k * q1 * q2) / r²

    Where k = Coulombs constant.

    Since q1 = q2 = q,

    F = (k * q²) / r²

    Inputting all the values:

    4 = (9 * 10^9 * q²) / 2²

    => 16 = (9 * 10^9 * q²)

    => q² = 16 / (9 * 10^9)

    q² = 1.78 * 10^(-9)

    => q = 4.216 * 10^(-5) C

    The value of both charges is 4.216 * 10^(-5) C.

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