Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 55 degree above the horizontal. Ball 2 has twice the

Question

Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 55 degree above the horizontal. Ball 2 has twice the initial speed of ball 1. If ball 1 lands a distance d_1 from the initial point, at what distance d_2 does ball 2 land from the initial point? (Neglect any effects due to air resistance.)
d_2 = d_1
d_2 = 4d_1
d_2 = 8d_1
d_2 = 0.5d_1
d_2 = 2d_1

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Đan Thu 4 days 2021-07-19T14:22:10+00:00 1 Answers 1 views 0

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    2021-07-19T14:23:39+00:00

    Answer:

    d_2 = 4d_1

    Explanation:

    The range or horizontal distance covered by a projectile projected with a velocity U at an angel of θ to the horizontal is given by

    R = U²sin2θ/g

    Let the range or horizontal distance of ball 1 with initial velocity U projected at an angle θ = 55° be

    d_1 = U²sin2θ/g

    Let the range or horizontal distance of ball 2 with initial velocity V = 2U projected at an angle θ = 55° be

    d_2 = V²sin2θ/g

    = (2U)²sin2θ/g

    = 4U²sin2θ/g

    = 4d_1   (since d_1 = U²sin2θ/g)

    So, the ball 2 lands a distance d_2 = 4d_1 from the initial point.

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