Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-degrees above t

Question

Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-degrees above the forward direction .Find the magnitude and direction(relative to forward direction of the resultant force that these forces exert on the body)​

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Nho 4 years 2021-09-05T05:12:52+00:00 1 Answers 11 views 0

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  1. RobertKer
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    2021-09-05T05:13:53+00:00
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    Answer:

    F = (913.14 , 274.87 )

    |F| = 953.61 direction 16.71°

    Explanation:

    To calculate the resultant force you take into account both x and y component of the implied forces:

    \Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N

    Thus, the net force over the body is:

    F=(913.14N)\hat{i}+(274.87N)\hat{j}

    Next, you calculate the magnitude of the force:

    F=\sqrt{(913.14N)+(274.87N)^2}=953.61N

    and the direction is:

    \theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°

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