Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of

Question

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 18 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 29 cm such that the combination does not rotate?

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Trung Dũng 14 mins 2021-07-22T17:07:05+00:00 1 Answers 0 views 0

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    2021-07-22T17:08:39+00:00

    Answer:

    Explanation:

    Given that,

    Small wheel applied force

    F₁ = 50N

    Small wheel radius

    r₁ = 18cm

    Bigger wheel radius.

    r₂ = 29cm

    Bigger wheel applied force

    F₂ =?

    Since the combination of those forces did not cause the wheel to rotate,

    Then, Στ = 0

    F₁•r₁ —F₂•r₂ =

    50×18 — 29F₂ = 0

    900 = 29F₂

    F₂ = 900 / 29

    F₂ = 31.03 N

    The pulling force applied at the larger wheel is 31.03N

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