Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19 C and Coulom

Question

Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19 C and Coulomb’s constant is 8.987 × 109 N · m2/C2. Answer in units of m.

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Diễm Kiều 6 months 2021-08-07T16:27:47+00:00 1 Answers 2 views 0

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    2021-08-07T16:29:39+00:00

    Answer:

    The answer to your question is distance between these electrons

                                                       = 1.386 x 10⁻¹⁴ m

    Explanation:

    Data

    Force = F = 1.2 N

    distance = d = ?

    charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

    K = 8.987 x 10⁹ Nm²/C²

    Formula

    -To solve this problem use the Coulomb’s equation

      F = kq₁q₂ / r²

    -Solve for r²

      r² = kq₁q₂ / F

    -Substitution

      r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

    – Simplification

      r² = 2.306 x 10⁻²⁸ / 1.2

      r² = 1.922 x 10⁻²⁸

    -Result

      r = 1.386 x 10⁻¹⁴ m

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