Share

## Two charges are separated by a distance r. The distance between the charges is tripled to 3r. If the original force between the charges was

Question

Two charges are separated by a distance r. The distance between the charges is tripled to 3r. If the original force between the charges was 45N what is the new force between the charges A.5N B.15N C.75N D.135N

in progress
0

Physics
6 months
2021-08-27T06:45:09+00:00
2021-08-27T06:45:09+00:00 1 Answers
3 views
0
## Answers ( )

Answer:5NExplanation:The formula formula for calculating the force between charges is expressed as;

F = kq1q2/r²

If two charges are separated by a distance r and a force between them is 45N, then;

45 = kq1q2/r² ….1

If the distance between the charges is tripled to 3r, then;

F = kq1q2/(3r)²

F = kq1q2/9r² … 2

Divide both expressions

45/F = (kq1q2/r²)/(kq1q2/9r²)

45/F = kq1q2/r² * 9r²/kq1q2

45/F = 9

9F = 45

F = 45/9

F = 5N

Hence the new force between them will be 5N