Two charges are separated by a distance r. The distance between the charges is tripled to 3r. If the original force between the charges was

Question

Two charges are separated by a distance r. The distance between the charges is tripled to 3r. If the original force between the charges was 45N what is the new force between the charges A.5N B.15N C.75N D.135N

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6 months 2021-08-27T06:45:09+00:00 1 Answers 3 views 0

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    2021-08-27T06:46:44+00:00

    Answer:

    5N

    Explanation:

    The formula formula for calculating the force between charges is expressed as;

    F = kq1q2/r²

    If two charges are separated by a distance r and a force between  them is 45N, then;

    45 = kq1q2/r² ….1

    If the distance between the charges is tripled to 3r, then;

    F = kq1q2/(3r)²

    F = kq1q2/9r² … 2

    Divide both expressions

    45/F = (kq1q2/r²)/(kq1q2/9r²)

    45/F = kq1q2/r² * 9r²/kq1q2

    45/F = 9

    9F = 45

    F = 45/9

    F = 5N

    Hence the new force between them will be 5N

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