Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1400 kg and is approaching at 6.5 m/s due

Question

Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1400 kg and is approaching at 6.5 m/s due south. The second car has a mass of 550 kg and is approaching at 19.5 m/s due west What is the change in kinetic energy, in joules, for the collision

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Thạch Thảo 10 mins 2021-07-22T22:23:01+00:00 1 Answers 0 views 0

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    2021-07-22T22:24:43+00:00

    Answer:

    74,993.75Joules

    Explanation:

    Kinetic energy is defined as the energy possessed by a body by virtue of its motion. It is expressed mathematically as:

    Kinetic energy = 1/2MV²

    where:

    M is the mass of the body

    V is the velocity of the body

    For the first car:

    Mass = 1400kg

    Velocity = 6.5m/s

    Kinetic energy of the car = 1/2×1400×6.5²

    = 700×6.5²

    KE1 = 29,575Joules

    For the second car:

    Mass = 550kg

    Velocity = 19.5m/s

    K.E2 = 1/2×550×19.5²

    K.E2 = 275×19.5²

    K.E2 = 104,568.75Joules

    Change in kinetic energy

    KE2-KE1

    = 104,568.75 – 29,575

    = 74,993.75Joules

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )