Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the other. If they m

Question

Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the other. If they meet in 2 hours, what is the rate of each bus?

in progress 0
Khoii Minh 4 years 2021-08-24T12:28:59+00:00 1 Answers 11 views 0

Answers ( )

  1. Xavia
    0
    2021-08-24T12:30:16+00:00
    Reply

    Answer:

    The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

    Step-by-step explanation:

    Let’s define:

    R₁ = rate of bus 1, this is the faster one.

    R₂ = rate of bus 2, this is the slower one.

    We know that one bus travels 14mi/h slower, then:

    R₂ = R₁ – 14mi/h.

    Now we know that:

    Distance = Speed*Time.

    If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

    R₁*2h + R₂*2h = 304 mi

    Then we have the two equations:

    R₂ = R₁ – 14mi/h

    R₁*2h + R₂*2h = 304 mi

    The first step is to replace the first equation in the second one, to get:

    R₁*2h + (R₁ – 14mi/h)*2h = 304 mi

    And now we can solve this for R₁.

    R₁*2h + R₁*2h – 14mi/h*2h = 304 mi

    R₁*4h – 28mi = 304mi

    R₁*4h = 304mi + 28mi = 332mi

    R₁ = 332mi/4h = 83mi/h

    The faster bus moves at 83mi/h

    And we know that the slower one moves at 14mi/h slower than this, then:

    R₂ = R₁ – 14mi/h = 83mi/h – 14mi/h = 69 mi/h

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )