Two areas of similar triangles are 75 dm^2 and 48 dm^2 and the sum of their perimetres is 288 dm what is each triangles perimeter?

Question

Two areas of similar triangles are 75 dm^2 and 48 dm^2 and the sum of their perimetres is 288 dm what is each triangles perimeter?

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Neala 1 month 2022-12-27T05:10:12+00:00 2 Answers 0 views 0

Answers ( 2 )

    0
    2022-12-27T05:11:18+00:00
    Each triangle Perimeter is 128 dm and 160 dm.
    With similar geometric figures all around the dimensions, consider the ratios of the dimensions:
    length = 1-dimension: a:b
    area = 2-dimensions: a²:b²
    volume = 3-dimensions: a³:b³
    Given the areas (2-D) of the two figures, 75 dm² and 48 dm²
    the a²:b² ratio is 25:16. Therefore, the ratio of the perimeters (1-D) would be √25: √16 or 5: 4.
    Solving, 288  = x + (5/4)x
    x = 128 dm
    Therefore the other triangle = 288 – 128 = 160 dm.
    One triangle Perimeter is 128 dm and the other is 160 dm.

    0
    2022-12-27T05:11:59+00:00

    Person above is correct

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