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two 3.0 kg bullets are fired with speeds of 40 m/s and 80 m/s, respectivley. what are their kinetic energies
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Answers ( )
KE = 1/2mv^2
m = mass of object
v = velocity ( speed of object )
40m/s bullet :
3 x 40 = 120
120 x 1/2 = 60
Kinetic Energy of 40m/s bullet: 60J
80m/s bullet:
3 x 80 = 240
240 x 1/2 = 120
Kinetic Energy of 80m/s bullet: 120J