two +1C charges are separated by 3000m. What is the magnitude of the electric force between them?

Question

two +1C charges are separated by 3000m. What is the magnitude of the electric force between them?

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Mít Mít 1 month 2021-08-01T22:54:13+00:00 2 Answers 4 views 0

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    0
    2021-08-01T22:55:51+00:00

    Answer:

    1000 N

    Explanation:

    The Electric Force between two charged particles with charges q1 and q2 respectively, separated by a distance, d, is given as:

    F = (k * q1 * q2) / d²

    Where k = Coulombs constant

    From the question:

    Charge of first particle = charge of second particle = q = +1 C

    Distance between both particles, d = 3000 m

    Therefore, Electric Force is:

    F = (9 * 10^9 * 1 * 1) / (3000²)

    F = (9 * 10^9) / (9 * 10^6)

    F = 1 * 10^3 N = 1000 N

    The electric force between both charges is 1000 N.

    0
    2021-08-01T22:55:59+00:00

    Answer:

    1000 N

    Explanation:

    The electric force between two charges is given as

    F = kq’q/r²……………………. Equation 1

    Where F = electric force between the charges, q’ = magnitude of the first charge, q = magnitude of the second charge, r = distance between the charges, k = coulombs constant

    Given: q’ = q = 1 C, r = 3000 m, k = 9×10⁹ Nm²/kg²

    Substitute into equation 2

    F = 1²×(9×10⁹)/3000²

    F = 1000 N.

    Hence the magnitude of the electric force between them = 1000 N

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