To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz , 1120 HzHz ,

Question

To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz , 1120 HzHz , and 1440 HzHz . It is unknown whether harmonics below 800 HzHz and above 1440 HzHz exist in the pipe. What is the length of the pipe

in progress 0
Thu Thảo 4 days 2021-07-18T23:26:14+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-18T23:27:55+00:00

    Answer:

    Length of the pipe = 53.125 cm

    Explanation:

    given data

    harmonic frequency f1  = 800 Hz

    harmonic frequency f2  = 1120 Hz

    harmonic frequency f3  = 1440 Hz

    solution

    first we get here fundamental frequency that  is express as

    2F = f2 – f1    ……………1

    put here value

    2F = 1120 – 800

    F = 160 Hz

    and

    Wavelength is express as

    Wavelength  = Speed ÷ Fundamental frequency    …………….2

    here speed of waves in air  = 340 m/s

    so put here value

    Wavelength  =340 ÷ 160

    Wavelength   = 2.125 m

    so

    Length of the pipe will be

    Length of the pipe = 0.25 × wavelength    ………………….3

    put here value

    Length of the pipe = 0.25 × 2.125

    Length of the pipe = 0.53125 m

    Length of the pipe = 53.125 cm

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )