To compare two products such as colas, a random sample is selected to taste two types of colas (A and B). Each selected subject tastes both

Question

To compare two products such as colas, a random sample is selected to taste two types of colas (A and B). Each selected subject tastes both colas and selects his/her preferred cola. What sample size would be needed to ensure that the margin of error in the brand preference is less than 5 percentage points in more than 95% of experiments

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Thiên Hương 4 years 2021-08-16T01:59:57+00:00 1 Answers 38 views 0

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    2021-08-16T02:01:14+00:00

    Answer: The sample size would be needed = 385

    Step-by-step explanation:

    Let p be the prior population proportion.

    Margin of error = E

    When not estimate of p is given , the formula to calculate the minimum sample size n = 0.25(\dfrac{z^*}{E})^2 , where z* = critical value for given confidence interval.

    Here z* for 95% confidence level is 1.96.

    E=5%=0.05

    Then n=0.25(\dfrac{1.96}{0.05})^2\approx385

    Hence, the sample size would be needed = 385

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