Tìm x , biết : a, -32/(-2)^3=4 b,8/2^x-1=2 c,(1/2)^2x-1=1/8 d,x/4 / 2 = 4/ x/2 Mn giúp e zới ạ

a) $\dfrac{-32}{(-2)^3}$

$=\dfrac{-32}{-8}=4=VP$ (ĐPCM)

b) $(\dfrac{8}{2})^{x-1}=2$

$↔4^{x-1}=2$

$↔(2^2)^{x-1}=2$

$→2^{2x-2}=2$

$↔2x-2=1$

$↔2x=3$

$↔x=\dfrac{3}{2}$

c) $(\dfrac{1}{2})^{2x-1}=\dfrac{1}{8}$

$↔(\dfrac{1}{2})^{2x-1}=(\dfrac{1}{2})^3$

$↔2x-1=3$

$↔2x=4$

$↔x=2$

d) $\dfrac{x}{4}:2=4:\dfrac{x}{2}$

$↔\dfrac{x}{4}.\dfrac{1}{2}=4.\dfrac{2}{x}$

$↔\dfrac{x}{8}=\dfrac{8}{x}$

$↔x^2=8.8=64$

\(↔\left[ \begin{array}{l}x=\sqrt{64}=8\\x=-\sqrt{64}=-8\end{array} \right.\)