tìm x biết: a) (2x+3)(x-1)+(2x-3)(1-x)=0
b)(x+1)(6x^2+2x)+(x-1)(6x^2+2x)=0
tìm x biết: a) (2x+3)(x-1)+(2x-3)(1-x)=0 b)(x+1)(6x^2+2x)+(x-1)(6x^2+2x)=0
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tìm x biết: a) (2x+3)(x-1)+(2x-3)(1-x)=0
b)(x+1)(6x^2+2x)+(x-1)(6x^2+2x)=0
Nem
Đáp án:
a.`x=1`
b.\(\left[ \begin{array}{l}x=0\\x=\frac{-1}{3}\end{array} \right.\)
Giải thích các bước giải:
`a) (2x+3)(x-1)+(2x-3)(1-x)=0`
`⇒(2x+3)(x-1)-(2x-3)(x-1)=0`
`⇒6(x-1)=0`
`⇒`\(\left[ \begin{array}{l}6=0(Loại)\\x-1=0\end{array} \right.\)
`⇒x-1=0`
`⇒x=1`
`b)(x+1)(6x^2+2x)+(x-1)(6x^2+2x)=0`
`⇒(6x^2+2x)(2x)=0`
`⇒2x(3x+1)2x=0`
`⇒`\(\left[ \begin{array}{l}x=0\\x=\frac{-1}{3}\end{array} \right.\)
Latifah
Đáp án:
`a) x=1`
`b) x=0` hoặc `x=-1/3`
Giải thích các bước giải:
`a) (2x+3)(x-1)+(2x-3)(1-x)=0`
`⇔(2x+3)(x-1)-(2x-3)(x-1)=0`
`⇔(x-1)(2x+3-2x+3)=0`
`⇔6(x-1)=0`
`⇔x-1=0`
`⇔x=1`
vậy `x=1`
`b) (x+1)(6x^2+2x)+(x-1)(6x^2+2x)=0`
`⇔(6x^2+2x)(x+1+x-1)=0`
`⇔2x.2x(3x+1)=0`
`⇔4x^2(3x+1)=0`
`⇔`\(\left[ \begin{array}{l}4x^2=0\\3x+1=0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=0\\x=-1/3\end{array} \right.\)
vậy `x=0` hoặc `x=-1/3`