tìm x: (3-x)^2 + 1/2x(2x^2 -6x-4)=4 Question tìm x: (3-x)^2 + 1/2x(2x^2 -6x-4)=4 in progress 0 Môn Toán Philomena 5 years 2020-11-02T13:14:05+00:00 2020-11-02T13:14:05+00:00 2 Answers 90 views 0
Answers ( )
`(3-x)^2 + 1/2x(2x^2 -6x-4)=4`
`⇔ 9-6x+x^2-x^3-3x^2-2x=4`
`⇔ x^3+2x^2+8x-5=0`
`⇔ x \approx 0,53`
Đáp án:
Giải thích các bước giải:
`(3-x)^2 + 1/2x(2x^2 -6x-4)=4`
`⇔ 9-6x+x^2-x^3-3x^2-2x=4`
`⇔ x^3+2x^2+8x-5=0`
`⇔ x \approx 0,53`
Vậy `S={0,53}`