Three students Tahat, Promi and Kabi, Appeared at an examination. Promi secured 11 marks less than Tahat, 5 marks more than kabi and again.

Question

Three students Tahat, Promi and Kabi, Appeared at an examination. Promi secured 11 marks less than Tahat, 5 marks more than kabi and again. Tahat’s marks were 75% of the sum of Promi and Kabi’s marks. Find out their individual marks

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Thành Đạt 4 years 2021-08-26T08:17:37+00:00 1 Answers 11 views 0

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  1. linhdan
    0
    2021-08-26T08:18:38+00:00
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    Answer:     Tahat= 40.5 marks    Promi =29.5 marks,  Kabi =24.5 marks

    Step-by-step explanation:

    Step 1

    Let the marks be represented as  x+11, x and x-5 for Tahat, Promi and Kabi respectively

    and Tahat’s marks which was 75% of the sum of Promi and Kabi’s marks be expressed as

    x+11 = 75/100(x + x-5)  

    Step 2 — Solving

    x+11 = 75/100(x + x-5)  

    x+ 11 = 3/4(2x-5)

    x+11= 6x-15/4

    4x+44=6x-15

    44+15=2x

    x= 59/2= 29.5,

    A) x= Promi’s  mark was 29.5

    B)Promi secured 5 marks more than kabi

    Therefore, Kabi’s mark was 5 marks less than Promi

    = x-5

    29.5- 5= 24.5 marks

    C)Promi secured 11 marks less than Tahat, Therefore Tahat marks were 11 marks more than Promi

    x+11= 29.5 + 11= 40.5

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