Three resistors of values 2 Q, 3 Q and 5 Q are connected in series with a battery of voltage 6.0 V. Calculate the current through each of th

Question

Three resistors of values 2 Q, 3 Q and 5 Q are connected in series with a battery of voltage 6.0 V. Calculate the current through each of the resistors, and the current through the battery.

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Khánh Gia 4 years 2021-07-29T03:00:56+00:00 1 Answers 10 views 0

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  1. sori
    0
    2021-07-29T03:02:41+00:00
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    Answer:

    Current = 0.6 A

    Explanation:

    Given that,

    Three resistors 2 ohms, 3 ohms and 5 ohms are connected in series with a battery of voltage 6 V.

    In series combination of resistors, the current through each resistor is the same while the voltage divides.

    The equivalent resistance in this case is given by :

    R_{eq}=R_1+R_2+....

    Put all the values,

    R_{eq}=2+3+5\\\\R_{eq}=10\ \Omega

    Let I be the current. Using Ohm’s law,

    V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{6}{10}\\\\I=0.6\ A

    So, the current through each resistor and the current through the battery is equal to 0.6 A.

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